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Browse Prior Art Database

High-Efficiency Control-Voltage Regulator

IP.com Disclosure Number: IPCOM000046247D
Original Publication Date: 1983-Jun-01
Included in the Prior Art Database: 2005-Feb-07
Document File: 2 page(s) / 27K

Publishing Venue

IBM

Related People

Simi, VM: AUTHOR [+2]

Abstract

The circuit shown takes the input line voltage, normally 110 V AC, and generates a lower DC voltage, typically 12-24 volts. This function is accomplished without using a transformer or dissipating power in a voltage-dropping resistor. A bridge arrangement has capacitors C1 and C2 which are polar (DC) capacitors. The output of the bridge is applied across VZ, a zener diode which sets the output level at its breakdown voltage, VBD.

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High-Efficiency Control-Voltage Regulator

The circuit shown takes the input line voltage, normally 110 V AC, and generates a lower DC voltage, typically 12-24 volts.

This function is accomplished without using a transformer or dissipating power in a voltage-dropping resistor. A bridge arrangement has capacitors C1 and C2 which are polar (DC) capacitors. The output of the bridge is applied across VZ, a zener diode which sets the output level at its breakdown voltage, VBD.

Operation of the circuit is as follows: The AC line voltage is connected across the two terminals L1 and L2. By connecting diodes D1 and D3 to ground, as shown, lines L1 and L2 cannot go below ground (assuming ideal diodes). Thus, assuming an input of 200 sin lt and after initial transients, at the time when the input voltage is 0 volts across the input terminals L1 and L2, these terminals are at an equal voltage of approximately 100 volts to ground. At this time, the capacitor C1 or C2 that is being changed is at approximately 100-VBD volts, while the other capacitor is at approximately 100 volts.

Where L1 is rising with respect to L2, capacitor C1 is charging through D5, C0 and VZ, D4 and C2 (which is discharging). Once the voltage at L2 is at ground, any further changing of C1 will be through D5, C0 and VZ, and D3. As the voltage of L1 passes the maximum value (sin $t = 1), the voltage of L2 begins to increase. C2 is charged through D6, C0 and VZ, D2 and C1 (which is now discharging). The char...