Browse Prior Art Database

Moving and Tilting Mirror Imaging System

IP.com Disclosure Number: IPCOM000078577D
Original Publication Date: 1973-Feb-01
Included in the Prior Art Database: 2005-Feb-26
Document File: 2 page(s) / 41K

Publishing Venue

IBM

Related People

Horlander, FJ: AUTHOR

Abstract

Two moving mirrors 1 and 2 cause an image to be swept along a line 3 tangent to the surface of a drum 4. A sufficient condition for this Two moving mirrors 1 and 2 cause an image to be swept along a line 3 tangent to the surface of a drum 4. A sufficient condition for this to occur is that the optical axis (center ray) moves without angular deviation and that the conjugate length remains constant.

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Moving and Tilting Mirror Imaging System

Two moving mirrors 1 and 2 cause an image to be swept along a line 3 tangent to the surface of a drum 4. A sufficient condition for this Two moving mirrors 1 and 2 cause an image to be swept along a line 3 tangent to the surface of a drum 4. A sufficient condition for this to occur is that the optical axis (center ray) moves without angular deviation and that the conjugate length remains constant.

These conditions are met, if the angle alpha + Beta = 90 degrees - theta/2 and if the direction of motion of the mirror system is always along a line perpendicular to the line which bisects angle theta. The length of the optical path may be adjusted by moving the mirror system in the direction of the bisector of angle 8.

The mirror system may be rotated about the vertex of the two mirrors, without producing any effect upon the angular deviation or length of optical path. This allows the mirrors to be rotated in an arbitrary way about the vertex 7 during translation of the system, in order to clear obstructions and possibly to reduce the total mirror surface needed.

The diagram of Fig. 2, illustrates that two mirrors M1 and M2 rotated about their intersection "0" do not change the ray length or angular deviation of the ray. From the diagram, a=b, c=d, alpha+beta is a constant. Also: A=B, D=E. Therefore, e = f A + e + D = B + f + E A + e + D = A + e + D.

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