Browse Prior Art Database

Load Sharing Inverter Drive Utilizing Capacitor Switching

IP.com Disclosure Number: IPCOM000080992D
Original Publication Date: 1974-Mar-01
Included in the Prior Art Database: 2005-Feb-27
Document File: 2 page(s) / 32K

Publishing Venue

IBM

Related People

Hoffman, HS: AUTHOR

Abstract

A series of transistor switches 1-4 are driven in a cyclic action by timing signals A and B, so as to reduce an input voltage of 4V to a voltage V at the input of transformer 8. The timing signals are alternately active, and each one is made inactive before the other one comes active so as to assure proper operation. Capacitors 5-7 are connected as shown. The timing signals are applied repetitively so that the circuit assumes an equilibrium condition during which the operation is as set forth below.

This text was extracted from a PDF file.
At least one non-text object (such as an image or picture) has been suppressed.
This is the abbreviated version, containing approximately 60% of the total text.

Page 1 of 2

Load Sharing Inverter Drive Utilizing Capacitor Switching

A series of transistor switches 1-4 are driven in a cyclic action by timing signals A and B, so as to reduce an input voltage of 4V to a voltage V at the input of transformer 8. The timing signals are alternately active, and each one is made inactive before the other one comes active so as to assure proper operation. Capacitors 5-7 are connected as shown. The timing signals are applied repetitively so that the circuit assumes an equilibrium condition during which the operation is as set forth below.

During period A, switches 1 and 3 are on. This causes capacitor 5 to be charged slightly to a nominal voltage of 3V. Capacitor 5 and the input of transformer 8 are connected in series across the input voltage so that the voltage drop across the transformer 8 is V and current flows, assuming the standard from plus to minus, upwardly through the input winding as shown. At the same time, capacitor 6 which has previously been charged to a voltage of 2V is now connected through switch 3 in series with capacitor 7 and the input winding. This causes capacitor 6 to discharge slightly while capacitor 7 is thereby charged to a nominal voltage V and current flows in the direction, as indicated previously.

During the second period, when B is active, switches 1 and 3 are off and switches 2 and 4 are on. This causes capacitor 5 to discharge through capacitor 6 and the input winding of transformer 8 whereby current now flows...