Browse Prior Art Database

Analog To Digital Conversion Using Cryotrons

IP.com Disclosure Number: IPCOM000098411D
Original Publication Date: 1960-Sep-01
Included in the Prior Art Database: 2005-Mar-07
Document File: 2 page(s) / 52K

Publishing Venue

IBM

Related People

Strohm, WG: AUTHOR

Abstract

A number of superconductive cryotrons arranged in a matrix are employed in an analog to digital converter. Each cryotron has one or more associated control conductors and switches between the superconducting and normal resistance states when the vector sum of the normalized control conductor currents exceeds 1/2.

This text was extracted from a PDF file.
At least one non-text object (such as an image or picture) has been suppressed.
This is the abbreviated version, containing approximately 74% of the total text.

Page 1 of 2

Analog To Digital Conversion Using Cryotrons

A number of superconductive cryotrons arranged in a matrix are employed in an analog to digital converter. Each cryotron has one or more associated control conductors and switches between the superconducting and normal resistance states when the vector sum of the normalized control conductor currents exceeds 1/2.

A constant current I(s) is delivered to one of the 16 output lines 31 to 46 through a unique superconducting path, including the gate conductors of four cryotrons. This path is determined by the magnitude of the analog input current I having a normalized variation within the range O to 1. Table I lists the required biasing currents for each cryotron and the magnitude of the analog input current for which the cryotron is resistive. TABLE I

Cryo-

Cryotron Bias Resistive tron Bias Resistive No. Current When No. Current When 1 I(1) = 0 I> 1/2 16 I(16)= - 9/16 I < 1/16 2 I(2) = -1 I < 1/2 17 I(17) = 5/16 I > 3/16 3 I(3) = 1/4 I> 1/4 18 I(18) = -11/16 I < 3/16 4 I(4) = - 3/4 I < 1/4 19 I(19) = 3/16 I > 5/16 5 I(5) = - 1/4 I> 3/4 20 I(20) = -13/16 I < 5/16 6 I(6) = -11/4 I < 3/4 21 I(21) = 1/16 I > 7/16 7 I(7) = 3/8 I> 1/8 22 I(22) = -15/16 I < 7/16 8 I(8) = - 5/8 I < 1/8 23 I(23) = -1/16 I > 9/16 9 I(9) = 1/8 I> 3/8 24 I(24) = -11/16 I < 9/16 10 I(1O) = 7/8 I < 3/8 25 I(25) = -3/16 I > 11/16 11 I(11) = -1/8 I> 5/8 26 I(26) = -13/16 I < 11/16 12 I(12)= -1 1/8 I < 5/8 27 I(27) = -5/16 I > 13/16 13 I(13)= - 3/8 I> 7/8...