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Constant Flyheight Magnetics Test with a Linear Actuator

IP.com Disclosure Number: IPCOM000122536D
Original Publication Date: 1991-Dec-01
Included in the Prior Art Database: 2005-Apr-04
Document File: 3 page(s) / 55K

Publishing Venue

IBM

Related People

Buettner, DC: AUTHOR [+2]

Abstract

Described is how a head on a linear actuator can be made to match the skew/radius profile of a head on a rotary actuator. This is accomplished by mounting the head on the linear actuator and the centerline of the linear actuator, as shown in Fig. 1.

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Constant Flyheight Magnetics Test with a Linear Actuator

      Described is how a head on a linear actuator can be made
to match the skew/radius profile of a head on a rotary actuator.
This is accomplished by mounting the head on the linear actuator and
the centerline of the linear actuator, as shown in Fig. 1.

      Fig. 1 shows that the skew, s, between the centerline of the
head and the tangent to track is
      (1) s = a - b

      The offset, d, of the head from the radial centerline is
      (2) d = R*sin(b)

      One way to optimize the offset and the angle, a, between the
head and the actuator for a particular rotary actuator is to solve
equations (1) and (2) for the angle a and the offset so that the
linear actuator head will match the rotary actuator head in skew at
the ID track and the OD track.  Substitution of equation (1) into
equation (2) allows the offset to be written as a function of the
track radius, skew, and angle a.
      (3) d = R*sin(a-s)

      If two pairs of values for the track radius and skew are known,
it is possible to solve for the offset and angle a.
      (4) a = arctan{(R1*sin(sl) - R2*sin(s2))/(R1*cos(s1) - R2*cos
              (s2))}
      and
      (5) d = R1*sin{arctan{(R1*sin(s1) - R2*sin(s2))/(R1*cos(s1) -
              R2*cos(s2))} - s1}

      For example, the head in one rotary actuator file flies with
about 5.7 degrees of skew at the ID track (23.3...